Register
What is the value for x in this equation? log(6x + 5) – log2 = log5
99.2k views
5 votes
What is the value for x in this equation?
log(6x + 5) – log2 = log5

User Biplob Biswas
by
8.5k points

1 Answer

1 vote
Log (6x+5)-log2=log 5
log (6x+5)=log 5+log 2

log 5 =0.698970004...
log 2=0.301029995

log 5 + log 2=1

log(6x+5)=1
log(6x+5)=log 10

Then:
6x+5=10
6x=10-5
6x=5
x=5/6

Answer: the value for x in this equation is 5/6.



User Doug Reeder
by
9.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!