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The equation for the reaction between Al(s) and Pb+2(aq) is:

2Al(s) + 3Pb+2(aq) 2Al+2(aq) + 3Pb(s)

Therefore, for each 2 moles of Al(s) that are used, how many moles of Pb(s) are formed?

From the 0.011 mole of Al(s) consumed, calculate the number of moles of Pb(s) that should have been formed: mole(s)

User Pod Mays
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2 Answers

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Answer:

3 moles of Pb(s) formed for each 2 moles of Al(s) consumed

0.0165 moles of Pb(s)should have been formed when 0.011 moles of Al(s) consumed

Explanation:

We are given that the equation for the reaction between Al(s) and Pb+2(aq) is

given below:


2Al(s)+3Pb+2(aq)\rightarrow 2Al+3(aq)+3Pb(s)

2 moles of Al(s) consumed then number of Pb(s) formed=3 moles

1 mole of Al(s) consumed then number of Pb(s) formed=
(3)/(2) moles

0.011 moles of Al(s) consumed then number of moles of Pb(s) formed=
(3)/(2)* 0.011=0.0165 moles

Answer: 3 moles of Pb(s) formed when 2 mole of Al(s) consumed

0.0165 moles of Pb(s) should have been formed when 0.011 moles of Al(s) consumed

5 votes

Answer:

For each 2 moles of Al(s) that are used, 3 moles of Pb(s) are formed.

0.0165 moles of Pb(s) that should have been formed From the 0.011 mole of Al(s) consumed

Explanation:

Given :

The equation for the reaction between Al(s) and Pb+2(aq) is:

2Al(s) + 3Pb+2(aq) 2Al+2(aq) + 3Pb(s)

To find: Therefore, for each 2 moles of Al(s) that are used, how many moles of Pb(s) are formed?

From the 0.011 mole of Al(s) consumed, calculate the number of moles of Pb(s) that should have been formed: mole(s)

Solution:

Now to calculate the how many moles of Pb(s) are formed for each 2 moles of Al(s) that are used

Consider the given equation.

So, we can see that for each 2 moles of Al(s) that are used, 3 moles of Pb(s) are formed.

Now , for 2 moles of Al(s) no. of moles of Pb(s) produced = 3

For 1 moles of Al(s) no. of moles of Pb(s) produced =
(3)/(2)

For 0.011 mole of Al(s) consumed no. of moles of Pb(s) produced :


(3)/(2) * 0.011


0.0165

Thus 0.0165 moles of Pb(s) that should have been formed From the 0.011 mole of Al(s) consumed .

User Tijuan
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