Question

What is the distance between P(−4, 3) and Q(6, 1)

Answer 1

`A(x_A;\ y_A);\ B(x_B;\ y_B).\\\\Distance\ d\ between\ A\ and\ B:\\\\d=√((x_B-x_A)^2+(y_B-y_A)^2)`



`P(-4;\ 3);\ Q(6;\ 1)\\\\|PQ|=√((6-(-4))^2+(1-3)^2)=√(10^2+(-2)^2)=√(100+4)\\\\=√(104)=√(4\cdot26)=\sqrt4\cdot√(26)=2√(26)`

Answer 2

The distance between P ( -4, 3) & Q (6,1)


`PQ = √(104) = 10.2`

So, 10.2 is your answer