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21 votes
21 votes
3. Explain why the equation 6lx] + 25 = 15 has no solution. O When one solves, they arrive at a step where x is equal to a negative number. Since x can never be negative inside of the absolute value bars, there is no solution. O The statement is false. There is a solution. O When one solves, they arrive at a step where Ixl is equal to a negative number. Since I xl can never be negative, there is no solution. O When one solves, they arrive at a step where [x] is equal to a fraction that may not be represented as an integer. Since | xl must be an integer, there is no solution.

3. Explain why the equation 6lx] + 25 = 15 has no solution. O When one solves, they-example-1
User CaptainPlanet
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1 Answer

14 votes
14 votes

To get the solution to the question, we will attempt to solve the absolute value equation:


6|x|+25=15

Step 1: Subtract 25 from both sides of the equation


\begin{gathered} 6\lvert x\rvert+25-25=15-25 \\ 6|x|=-10 \end{gathered}

Step 2: Divide both sides of the equation by 6


\begin{gathered} (6|x|)/(6)=-(10)/(6) \\ |x|=-(5)/(3) \end{gathered}

Step 3: Recall that an absolute value is nonnegative, meaning it is either zero or positive. The output of the absolute value operator is never negative. Therefore, there is no solution


\mathrm{No\:Solution\:for}\:x\in \mathbb{R}

ANSWER: The THIRD OPTION is correct.

User Xaver
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