Question

Find the rate of change of the function h(x) = 4x – 3 on the interval 0 ≤ x ≤ 1.The rate of change is

Answer 1

Given the function h(x) = 4x - 3 on the interval 0 ≤ x ≤ 1, we have to find the rate of change of function.

Step-by-step explanation

`\begin{gathered} h\mleft(0\mright)=4\left(0\right)-3=-3 \\ h\mleft(1\mright)=4\left(1\right)-3=4-3=1 \\ rate\text{ of change=}(h\mleft(x_2\mright)-h\mleft(x_1\mright))/(x_2-x_1)=(1-(-3))/(1-0)=4 \end{gathered}`

Answer: 4