Question

What is the solution to the equation?square root (2x+10) -6 = 2I need to understand the step by step steps I would take to solve this.

Answer 1

To answer this question we will use the following property:

`(\sqrt[]{a})^2=a\text{.}`

Adding 6 to the given equation we get:

`\begin{gathered} \sqrt[]{2x+10}-6+6=2+6, \\ \sqrt[]{2x+10}=8. \end{gathered}`

Taking the above equation to the power of 2 we get:

`(\sqrt[]{2x+10})^2=8^2\text{.}`

Therefore:

`2x+10=64.`

Subtracting 10 from the above equation we get:

`\begin{gathered} 2x+10-10=64-10, \\ 2x=54. \end{gathered}`

Finally, dividing the above equation by 2 we get:

`\begin{gathered} (2x)/(2)=(54)/(2), \\ x=27. \end{gathered}`

Answer: x=27.