82,077 views
39 votes
39 votes
In the right triangle shown, mA = 30° and BC = 6√2.

In the right triangle shown, mA = 30° and BC = 6√2.-example-1
User Harshil Kotecha
by
2.3k points

1 Answer

22 votes
22 votes

AC=14.7

Step-by-step explanation

Step 1

given the right triangle

a)let


\begin{gathered} angle=30 \\ opposite\text{ side=BC=6}√(2) \\ adjacent\text{ side=x} \end{gathered}

hence , we need a trigonometric function that relates those values, it is


tan\theta=\frac{opposite\text{ side}}{adjacent\text{ side}}

replace and solve for x(AC)


\begin{gathered} tan\text{ 30}=(6√(2))/(x) \\ x=\frac{6√(2)}{tan\text{ 30}} \\ x=(6√(2))/((1)/(√(3)))=(6√(2)√(3))/(1) \\ x=14.6969 \\ rounded \\ x=14.7 \end{gathered}

therefore, the answer is 14.7 ( decimal form)

I hope this helps you

In the right triangle shown, mA = 30° and BC = 6√2.-example-1
User Malka
by
3.6k points