Question

answer question 12 pleasepart b: if the frequency is doubled how many loops will be produced in the string?

Answer 1

Part A: c. 240 Hz

Part B: 4 loops

Explanation:

Given:

String length =20 cm = 0.2 m

When there are two loops, the length of the string is equal to the wavelength, therefore

Wavelength (λ) = 0.2 m

Speed (v) = 48 m/s

Part A:

We can calculate the frequency using the following formula:

`\begin{gathered} f=(v)/(λ) \\ \\ \text{ We replacing:} \\ \\ f=(48)/(0.2) \\ \\ f=240\text{ Hz} \end{gathered}`

The frequency is equal to 240 Hz, so the correct answer is c. 240 Hz

Part B:

We can determine the frequency when the number of loops is doubled knowing that these are proportional, as shown in the following figure:

This means that if the frequency is doubled, the number of loops is doubled, therefore, there will be 4 loops (2*2)