Question

Need help with homework

Answer 1

I will use the quadratic formula to solve and find the solutions of the equation:

`\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In the case of 4x^2 - 28x + 130:

a = 4

b = -28

c = 130

Thus:

`\frac{-(-28)\pm\sqrt[]{-28^2-4*4*130}}{2*4}`

`\frac{28\pm\sqrt[]{-1296}}{8}`

`(28\pm36i)/(8)`

The first solution will be:

`(28+36i)/(8)=3.5+4.5i`

The second solution will be:

`(28-36i)/(8)=3.5-4.5i`

Answer:

`x=\mleft\lbrace(28+36i)/(8),(28-36i)/(8)\mright\rbrace`