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4 votes
Which sum is equal to x^2+6x-5/x^2-25

User Jvf
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2 Answers

4 votes
1/x+5 + x/x-5 i think so
User Joseph Spiros
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7 votes

Answer: The sum will be given as


1+(6x+20)/(x^2-25)

Explanation:

Since we have given that


(x^2+6x-5)/(x^2-25)

We just need to simplify and get the sum :


\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^2+6x-5\mathrm{\:and\:the\:divisor\:}x^2-25\mathrm{\::\:}(x^2)/(x^2)=1\\\\\mathrm{Quotient}=1\\\\\mathrm{Multiply\:}x^2-25\mathrm{\:by\:}1:\:x^2-25\\\\\mathrm{Subtract\:}x^2-25\mathrm{\:from\:}x^2+6x-5\mathrm{\:to\:get\:new\:remainder}\\\\\mathrm{Remainder}=6x+20\\\\(x^2+6x-5)/(x^2-25)=1+(6x+20)/(x^2-25)

Hence, the sum will be given as


1+(6x+20)/(x^2-25)

User Eljenso
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