Question

How do I solve this?

Answer 1

Explanation:

`y^(2) = 36 - {x}^(2) \\ {x}^(2) + {y}^(2) = 36 \\ ( x - 0)^(2) + (y - 0)^(2) = {(6)}^(2) \\`

The standard equation of a circle is (x - h)² + (y - k)² = r²

where (h,k) is the center and r is the radius.

Therefore, (0,0) is the center and 6 is the radius.