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The height h(in feet) of a project tile with an initial vertical Velocity of 96 feet/seconds is modeled by the function h=-16t^2+96t, where t is the time, in seconds Answer the following

The height h(in feet) of a project tile with an initial vertical Velocity of 96 feet-example-1
User Tommybee
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1 Answer

29 votes
29 votes

The function of the height is,


h=-16t^2+96t

where,


t=\text{time in seconds}
h=\text{height}

We will start substituting the values of t starting from when t= 0 till the function gives us negative.

Step 1:


\begin{gathered} when\text{ t=0,} \\ h=-16(0)^2+96(0)=0+0=0ft \end{gathered}
\begin{gathered} \text{when t=1} \\ h=-16(1)^2+96(1)=-16+96=80ft \end{gathered}
\begin{gathered} \text{when t=2} \\ h=-16(2)^2+96(2)=-64+192=128ft \end{gathered}
\begin{gathered} \text{when t=3} \\ h=-16(3)^2+96(3)=-144+288=144ft \end{gathered}
\begin{gathered} \text{when t=4} \\ h=-16(4)^2+96(4)=-256+384=128ft \end{gathered}
\begin{gathered} \text{when t=5} \\ h=-16(5)^2+96(5)=-400+480=80ft \end{gathered}
\begin{gathered} \text{when t=6} \\ h=-16(6)^2+96(6)=-576+576=0ft \end{gathered}
\begin{gathered} \text{when t=7} \\ h=-16(7)^2+96(7)=-784+672=-112ft \end{gathered}

Step 2:

Step 3: We are to plot the graph and determine the highest point.

Hence, from the graph we can confirm that the time in which the projectile was in the air is 6seconds.

The height h(in feet) of a project tile with an initial vertical Velocity of 96 feet-example-1
The height h(in feet) of a project tile with an initial vertical Velocity of 96 feet-example-2
User Shamittomar
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