Question

A bag of M&M's has 2 red, 3 green, 8 blue, and 6 yellow M&M's. What is the probability of randomly picking: (Round to 4 decimal places)

Answer 1

Given:

A bag of M&M's has 2 red, 3 green, 8 blue, and 6 yellow M&M's.

Total M&M's = 2+3+8+6=19

a) The probability of randomly picking a yellow M&M's is,

`\begin{gathered} P=\frac{Number\text{ of possible outcomes}}{\text{Total number of outcomes}} \\ P=(6)/(19)=0.3158 \end{gathered}`

b) The probability of randomly picking a blue or green M&M's is,

`P=(8)/(19)+(3)/(19)=(11)/(19)=0.5789`

c) The probability of randomly picking a orange M&M's is,

As there are no orange M&M's in the bag, the probability is,

`P=(0)/(19)=0`