Question

What are all of the answers for these questions? Use 3.14 for pi. Please do not use a file to answer, I cannot read it.

Answer 1

SOLUTION to question 8.

The area of the shaded portion is caculated by using the formula

`\text{Area of external circle- Area of the internal circle}`

Hence

Area of the bigger circle will be obtain using the formula

`\begin{gathered} \pi R^2 \\ \text{where} \\ \pi=3.14, \\ R=(6)/(2)=3 \end{gathered}`

substitute into the formula, we have

`=3.14*3^2=3.14*9=28.26cm^2`

Hence

Area of the bigger circle is 28.26cm²

There area of the bigger circle will be

`\begin{gathered} \pi r^2 \\ \text{where r=}\frac{\text{2}}{2}=1 \\ \\ 3.14*1^2=3.14cm^2 \end{gathered}`

Hence

The ares of the internal circle is 3.14cm²

Hence

There area of the shaded portion is

`28-26-3.14=25.12cm^2`

Therefore

The area of the of the shaded portion is 25.12cm²