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For a cosine function with amplitude A=0.75 and period T=10, what is y(4)?

User Nvcken
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2 Answers

3 votes
2π/T = 2π/10 = π/5

y(x) = A sin (wx) = 0.75 sin (πx/5)

y(4) = 0.75 sin (4π/5) = 0.4408389392... ≈ 0.441
User Damian Avila
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4 votes

Answer:

y(4) = -0.606

Step-by-step explanation:

Given that,

The amplitude of cosine function, A = 0.75

Time period, T = 10

The cosine function is given by :


y=A\ cos(\omega t)

Since,
\omega=(2\pi)/(T)


y=A\ cos((2\pi)/(T)t)


y=0.75\ cos((2\pi)/(10)t)

We need to find y (4). Put t = 4 in above equation as :


y(4)=0.75\ cos((2\pi)/(10)* 4)

y(4) = -0.606

Hence, this is the required solution.

User Boysie
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