Question

in one baseball season, peter hit twice the difference of the number of home runs alice hit and 6. altogether, they hit 18 home runs. hohw many home runs did each player hit that season?

Answer 1

Let Peter's hit be x and Alice's runs be y.
x = 2(y - 6) . . . (1)
x + y = 18 . . . (2)

Putting (1) into (2) gives,
2y - 12 + y = 18
3y = 18 + 12 = 30
y = 30/3 = 10
x = 2(10 - 6) = 2(4) = 8

Therefore, Peter hit 8 home runs and Alice hit 10 home runs.