Question

Find the second, fourth, and eleventh terms of sequence described by the rule.A(n) = 3 + (n - 1)(5)--------------------------------I already have:
`a(2) = 8`
`a(4) = 18`
`a(11) = ...`However now, I need to find A(11) = ?Please help me find A(11) =

Answer 1

Step 1

Given;

`A(n)=3+(n-1)(5)`

Required; To find A(11)

Step 2

n= 11, Therefore, substitute 11 for n

`\begin{gathered} A(11)=3+(11-1)(5) \\ A(11)=\text{ 3 + 10(5)} \end{gathered}`
`\begin{gathered} A(11)=\text{ 3+50} \\ A(11)=53 \end{gathered}`

Hence, A(11) = 53