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F(x) = (x^2 - 4) / √x F'(x) = ...?
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F(x) = (x^2 - 4) / √x
F'(x) = ...?

User Ayinde
by
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1 Answer

5 votes

f(x)=(x^2-4)/(√(x))\\\\f'(x)=((x^2-4)'(√(x))-(x^2-4)(√(x))')/((√(x))^2)=(2x√(x)-(1)/(2√(x))(x^2-4))/(x)\\\\=((2x√(x)\cdot2√(x))/(2√(x))-(x^2-4)/(2√(x)))/(x)=(4x^2-x^2+4)/(2x√(x))=(3x^2+4)/(2x√(x))
User BytesOfMetal
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