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a jar of cookies contains 18 different types of cookies. Each type is equally likely to be chosen. Based on your simulation, how many times must a cookie be chosen in order to get each type?

User Amflare
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2 Answers

3 votes
1/18th of a chance each time you draw. But it really depends on how many are in the jar. I'd say 18.
User Samullen
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1 vote

Answer:

Number of Cookies in the jar =18={A,B,C.......,...P,Q,R}

It is given that, each type is equally likely to be chosen.

Probability of an event


=\frac{\text{Total favorable outcome}}{\text{Total possible outcome}}

Probability of Getting any of the cookies out of 18 cookies


=(1)/(18)

When number of outcomes increases , probability of getting each type of cookie will be Higher.

So, there are 18 cookies , when number of each type of cookie will be

=18 × 18

=324 cookies ,means each distinct single cookie is available in 18 containers, means that is there is total of 324 containers.

So, out of 324 containers each cookie must be chosen 18 times.

User TechRemarker
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