Question

i need help!!! write an equation in point-slope form of the line through point j(4, –4) with slope 4. a. y 4=4(x 4) b. y 4=4(x-4) c. y-4=4(x 4) d. y 4=4(x-4)

Answer 1

The equation of line passing through (4,-4) and having slope '4' is:
`y+4=4(x-4)`

Explanation:

The equation of a line passing through a point
`(x_(1),y_(1))` and having slope 'm' is given by:

`y-y_(1) =m(x-x_(1))`

Here we are given that the line passes through the point (4,-4) and having slope 4.

⇒
`(x_(1),y_(1))=(4,-4)` and
`m=4`

Hence, the equation of line is:

`y+4=4(x-4)`

Answer 2

Required equation is y - y1 = m(x - x1); where m = 4 and (x1, y1) = (4, -4)
y - (-4) = 4(x - 4)
y + 4 = 4(x - 4)