Answer:
a). Number of quarters = 11
b). Option C.
Explanation:
a). Let Thomas has number of dimes = d
and number of quarters = q
It is given that he has the number of dimes 3 more than the three times the number of quarters.
d = 3q + 3 ------(1)
Thomas has $6.35 in dimes and quarter.
Value of dimes = 0.10d
Value of quarters = 0.25q
0.10d + 0.25q = 6.35
10d + 25q = 635
2d + 5q = 127 ------(2)
We place the value of d from equation (1) in equation (2).
2(3q + 3) + 5q = 127
6q + 6 + 5q = 127
11q + 6 = 127
11q = 121
q = 11
Number of quarters are 11.
b). Since 1 dime = 10 cents
Therefore, from equation (1),
d = 10(3q + 3)
Option C is the answer.