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solve the following system of equations: x − 2y = 14 x 3y = 9 a) (1, 12) b) (−1, −12) c) (12, −1) d) (12, 1)

User Pinoniq
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1 Answer

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x - 2y = 14 . . . . . (1)
x + 3y = 9 . . . . . (2)

(1) - (2) => -5y = 5
y = 5/-5 = -1

From (1), x - 2(-1) = 14
x + 2 = 14
x = 14 - 2 = 12

Solution is (12, -1)
User Mark Wallace
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