259,043 views
9 votes
9 votes
A 131 kg electric motorcycle moving at 30 mph accelerates by 0.03 m/s^2 for 60 s in the same direction that it’s moving. What is the average velocity during this period? Answer in km/hr.

User Pranay Dutta
by
2.5k points

1 Answer

24 votes
24 votes

We would calculate the distance travelled by the motor by applying one of Newton's formula for calculating motion which is expressed as

s = ut + 1/2at^2

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

From the information given,

u = 30 mph

We would convert it to m/s

Recall,

1 mile = 1609.344 m

1 hour = 3600 s

Thus,

30mph = (30 x 1609.344)/3600

u = 13.4112 m/s

t = 60 s

a = 0.03m/s^2

Thus,

s = 13.4112 x 60 + 1/2 x 0.03 x 60^2

s = 804.672 + 54

s = 858.672 m

We would convert 858.672 m to km and 60s to hours. It becomes

858.672 m = 858.672/1000 = 0.858672 km

60s = 60/3600 = 1/60 hr

Average velocity = 0.858672 km/(1/60 hr)

Average velocity = 51.5 km/hr

User Laurette
by
3.0k points