We would calculate the distance travelled by the motor by applying one of Newton's formula for calculating motion which is expressed as
s = ut + 1/2at^2
where
s is the distance travelled
u is the initial velocity
t is the time
a is the acceleration
From the information given,
u = 30 mph
We would convert it to m/s
Recall,
1 mile = 1609.344 m
1 hour = 3600 s
Thus,
30mph = (30 x 1609.344)/3600
u = 13.4112 m/s
t = 60 s
a = 0.03m/s^2
Thus,
s = 13.4112 x 60 + 1/2 x 0.03 x 60^2
s = 804.672 + 54
s = 858.672 m
We would convert 858.672 m to km and 60s to hours. It becomes
858.672 m = 858.672/1000 = 0.858672 km
60s = 60/3600 = 1/60 hr
Average velocity = 0.858672 km/(1/60 hr)
Average velocity = 51.5 km/hr