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7x^2=9+x what are the values of x

Will give medal and points

User Sotomajor
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1 Answer

4 votes
7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x =
(-b \pm √(b^2 - 4ac) )/(2a) Plug in the a, b, and c values
x =
(- (-1) \pm √((-1)^2 - 4(7)(-9)) )/(2(7)) Cancel out the double negative
x =
(1 \pm √((-1)^2 - 4(7)(-9)) )/(2(7)) Square -1
x =
(1 \pm √(1 - 4(7)(-9)) )/(2(7)) Multiply 7 and -9
x =
(1 \pm √(1 - 4(-63) )/(2(7)) Multiply -4 and -63
x =
(1 \pm √(1 + 252) )/(2(7)) Multiply 2 and 7
x =
(1 \pm √(1 + 252) )/(14) Add 1 and 252
x =
(1 \pm √(253) )/(14) Split up the
\pm
x =
\left \{ {{ (1 + √(253) )/(14) } \atop { (1 - √(253) )/(14) }} \right.
The approximate square root of 253 is 15.905973.
x ≈
\left \{ { (1 + 15.905973)/(14) } \atop { (1 - 15.905973)/(14) }} \right Add and subtract
x ≈
\left \{ {{ (16.905973)/(14) } \atop { (14.905973)/(14) }} \right. Divide
x ≈
\left \{ {{1.2075} \atop {1.0647}} \right. Round to the nearest hundredth
x ≈
\left \{ {{1.21} \atop {1.06}} \right.


User Praxiteles
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