Question

Solve the system of linear equations below.
  2x + 3y = 2
  x + 6y = 4

Answer 1

2x+3y=2
x+6y=4
Multiply equation II by II
2x+3y=2
2x+12y=8
-------------
9y=6
y=6/9
y=2/3
Solving for x by replacing in equation 1;
2x+3*2/3=2
2x+2=2
2x=0
x=0

Answer 2

`(0, (2)/(3))`

Explanation:

Given the system of equation:

2x + 3y = 2 ....[1]

x + 6y = 4 . ...[2]

Multiply by 2 to both sides in [1] we get;

4x + 6y =4 ....[3]

Subtract equation [2] from [3] to eliminate y we get;

`4x-x = 0`

⇒
`3x = 0`

Divide both sides by 3 we have;

x = 0

Substitute the value of x in [1] we have;

2(0)+ 3y = 2

⇒
`0+3y =2`

⇒
`3y = 2`

Divide both sides by 3 we have;

`y = (2)/(3)`

Therefore, the solution for the given system of equation is,
`(0, (2)/(3))`