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Two positive integers $m$ and $n$ are chosen such that $m$ is the smallest positive integer with only two positive divisors and $n$ is the largest integer less than $100$ with exactly three positive divisors.
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Apr 24, 2017
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Two positive integers $m$ and $n$ are chosen such that $m$ is the smallest positive integer with only two positive divisors and $n$ is the largest integer less than $100$ with exactly three positive divisors. What is $m+n$?
Mathematics
middle-school
Kristian Barrett
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Kristian Barrett
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Hello,
we only have 3 divisors if n is a square of a prime (1,a,a²) with a<10
==>n=49
and m=2
m+n=49+2=51
Ycsun
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Apr 28, 2017
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Ycsun
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