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A circle has a radius of 6 inches. Find the area of a sector of this circle that is intercepted by a central angle measuring 30°. A. 2π. B. 3π. C. 6π. D. 12π

2 Answers

5 votes

Final answer:

The area of the sector is 3π square inches.

Step-by-step explanation:

To find the area of a sector of a circle, you need to use the formula:

Area of sector = (central angle/360) × πr²

In this case, the central angle is 30° and the radius is 6 inches. Plugging in these values, we get:

Area = (30/360) × π × 6² = (1/12) × π × 36 = 3π square inches

Therefore, the area of the sector is 3π, which corresponds to option B.

User Jpaugh
by
6.3k points
1 vote

Answer:

Option B is correct

Step-by-step explanation:

Area(A) of sector of the circle is given by:


A = \pi r^2 \cdot (\theta)/(360^(\circ)) ....[1]

As per the statement:

A circle has a radius of 6 inches.

⇒r = 6 inches

It is also given that a central angle is 30°


\theta = 30^(\circ)

Substitute the given values in [1] we have;


A = \pi \cdot 6^2 \cdot (30^(\circ))/(360^(\circ))


A = \pi \cdot 36 \cdot (1)/(12)


A = \pi \cdot 3

Simplify:


A = 3 \pi square inches

Therefore, the area of a sector of circle is, 3π inches

User Conf
by
6.7k points
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