Question

A number,half of the number, and 16 are added.the result is 43.What is the original number

Answer 1

Let n be the number,

a number (n)

half of the number (n/2)

and 16 are added and the result is 43

This will be :

`n+(n)/(2)+16=43`

Solve for the value of n.

Multiply both sides by 2 :

`2n+n+32=86`

Subtract 32 to both sides of the equation :

`\begin{gathered} 3n=86-32 \\ 3n=54 \end{gathered}`

Divide both sides by 3 :

`\begin{gathered} (3n)/(3)=(54)/(3) \\ n=18 \end{gathered}`

The answer is 18