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Simplify the expression
y^2/4+y/3+y^2/3-y/5

User Vasigorc
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1 Answer

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(y^2)/(4)+(y)/(3)+(y^2)/(3)-(y)/(5)=(3y^2)/(3\cdot4)+(4y^2)/(3\cdot4)+(5y)/(3\cdot5)-(3y)/(3\cdot5)\\\\=(3y^2)/(12)+(4y^2)/(12)+(5y)/(15)-(3y)/(15)=\boxed{(7y^2)/(12)+(2y)/(15)}\\\\or\\\\(7y^2)/(12)+(2y)/(15)=(7y^2\cdot5)/(12\cdot5)+(2y\cdot4)/(15\cdot4)}=(35y^2)/(60)+(8y)/(60)=\boxed{(35y^2+8y)/(60)}
User ImFonky
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