Question

A function is defined by fix) = 5(2-x). What is f(-1)?O 5O 5O 15053

Answer 1

• 
  `\sf{f(-1)=15}`

Solution:

Hi! First, what you need to do is expand the expression:

`\sf{f(x)=5(2-x)}`

`\sf{f(x)=10-5x`

Next, what you do is you plug in -1 for x, as the problem instructs:

`\sf{f(-1)=10-5(-1)}\\f(-1)=10+5\\f(-1)=15`

Problem solved! It's been a pleasure helping you.

Answer 2

Given function:

`f(x)=5(2-x)`
`f(-1)=5(2-(-1))`
`\begin{gathered} f(-1)=5(2+1) \\ =5*3 \\ =15 \end{gathered}`