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What is the exact value of x in the exponential equation −11 + e5x = 17?
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What is the exact value of x in the exponential equation −11 + e5x = 17?

User Iamrameshkumar
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1 Answer

5 votes
Start by getting e by itself

e^(5x) =28

take the natural log of both sides

ln e^(5x) =ln28

This lets you cancel e and leaves you with

5x=ln28

solve for x
x=.67
User Henhesu
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7.6k points
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