Question

HELP PLEASE.....EASY QUESTION!!!!

Answer 1

90% of confidence interval for the true population of club members who use compost

(0.44424 , 0.45576)

Explanation:

Step(i):-

Given that the size of the sample 'n' =200

Given that the sample proportion

p = 45% = 0.45

Level of significance = 90% or 10%

Critical value Z₀.₁₀ = 1.645

Step(ii):-

90% of confidence interval for the true population of club members who use compost

`(p^(-) - Z_(0.10) \sqrt{(p(1-p^(-) ))/(n) } , p^(-) + Z_(0.10) \sqrt{(p(1-p^(-) ))/(n) })`

`((0.45 - 1.645\sqrt{(0.45(1-0.45))/(200) } , 0.45 + 1.645\sqrt{(0.45(1-0.45))/(200) })`

(0.45 - 0.00576 , 0.45 +0.00576)

(0.44424 , 0.45576)

Final answer:-

90% of confidence interval for the true population of club members who use compost

(0.44424 , 0.45576)