Question

a box contains 6 red and 5 blue marbles. another box contains 5 red and 8 blue marbles. one box is selected at random and from that bag, one marble is drawn. what is the probability that the marble drawn is blue?

Answer 1

P(blue) = {(1/2) × (5/11)} + {(1/2) × (8/13)} = 5/22 + 4/13 = 153/286

Answer 2

The probability is 0.535

Explanation:

Given that a box contains 6 red and 5 blue marbles. another box contains 5 red and 8 blue marbles. one box is selected at random and from that bag, one marble is drawn.

we have to find the probability that the marble drawn is blue.

`Probability=\frac{\text{Favourable outcomes}}{\text{Total number of outcomes}}`

The probability can be find by formula

=P(first box)P(blue marble drawn from box 1)+P(second box)P(blue marble drawn from box 2)

`=(1)/(2)* (5)/(11)+(1)/(2)* (8)/(13)`

`(5)/(22)+(8)/(26)`

`(153)/(286)=0.535`