Question

The data in the table below represents the pressure of the gas as the temperature changes. Plot a graph of this data. Draw a trend line and calculate its slope. How are the variables related? What will the pressure of the gas be at 0°C? The data is:. Temp(c): 10, 25, 40, 55, 80. Pressure (torr): 723, 763, 800, 845, 900.

Answer 1

The variables are linearly related.

Slope of given data line is 2.5522

The pressure of the gas be at 0°C is 699.01 torr.

Explanation:

Given: The data in the table below represents the pressure of the gas as the temperature changes.

We have to plot the graph of the given data .

Consider the given Table,

On x - axis , we represents temperature of gas in °C and on y- axis , we represents the pressure of gas in torr.

We know plot the given data.

We obtained the equation of line as y = 2.5522 x + 699.01

Thus, The equation of line is given as y = mx + b , where m is slope and b is y intercept

Thus, Slope of given data line is 2.5522

and to calculate the pressure of the gas at 0°C is given by putting x = 0, we get

y = 699.01

Thus, The pressure of the gas be at 0°C is 699.01 torr.

Answer 2

The correct answer is:

The slope of the trend line is 2.55; as the temperature increases, the gas pressure increases as well.

Explanation:

The graph is attached. Using a graphing calculator to plot the data and run the regression, we get the figure attached. The value for a, the slope, is 2.55, and the value of b, the y-intercept, is 699.01. The line increases; this means as the x-value, the temperature, increases, so does the y-value, the pressure.