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A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the tickets?
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A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the tickets?

User Imamudin Naseem
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8.1k points

2 Answers

2 votes

Answer: 56 ways.

Explanation:

I got it right in the mastery test.

User Heaphach
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7.9k points
3 votes
The question involved the concept of combination because the order of the friends being picked are not considered. There are a total of 8 friends and 5 out of them are picked.
8C5 = 56
Therefore, there are 56 ways.
User Benui
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8.5k points
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