Question

If an object is projected upward with an initial velocity of 126 ft per​ sec, its height h after t seconds is h= -16^2+126t. Find the height of the object after 5 seconds

Answer 1

All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!

Answer 2

230 ft is the height of the object after 5 seconds

Explanation:

As per the statement:

If an object is projected upward with an initial velocity of 126 ft per​ sec.

The height h after t seconds is given by:

`h(t) = -16t^2+126t`

We have to find the height of the object after 5 seconds.

At t = 5 seconds

`h(5) = -16(5)^2+126(5)`

⇒
`h(5) = -16 \cdot 25+630`

⇒
`h(5) = -400+630`

Simplify:

h(5) = 230 ft

Therefore, the height of the object after 5 seconds is, 230 ft