Question

Determine the number of solutions that exist for the given equation.

0.75(x + 40) = 0.35(x + 20) + 0.35(x + 20)

Answer 1

0.75(x + 40) = 0.35(x + 20) + 0.35(x + 20)
0.75x + 30 = 0.35x + 7 + 0.35x + 7
0.75x = 0.70x + 14 - 30
0.75x - 0.70x = - 16
0.05x = -16
x = -16/0.05
x = -320

one solution

Answer 2

First, distribute the numbers outside the parentheses with those inside. That would be,
0.75x + 30 = 0.35x + 7 + 0.35x + 7
Simplifying,
0.75x + 30 = 0.70x + 40
The value of x from the equation is 200. Thus, the equation only has 1 solution and that is 200.