Question

What is the value of fraction 1 over 3x2 + 5.2y when x = 3 and y = 2?

12.4
13.4
14.4
16.4

Answer 1

`(1)/(3)x^2+5.2y\\\\for\ x=3\ and\ y=2\\\\(1)/(3)\cdot3^2+5.2\cdot2=(1)/(3)\cdot9+10.4=(9)/(3)+10.4=3+10.4=13.4`

Answer 2

B. 13.4

Explanation:

We have the fraction,
`L=(1)/(3)x^2+5.2y`.

It is required to find the value of the fraction when x = 3 and y = 2.

So, on substituting these values, we get,

`L=(1)/(3)(3)^2+5.2* 2`

i.e.
`L=(9)/(3)+10.4`

i.e.
`L=3+10.4`

i.e.
`L=13.4`

So, the value of the fraction is 13.4

Hence, option B is correct.