The correct answer is:
(13, −1)
Step-by-step explanation:
The points of the pre-image JKLM are:
J(-6, 2); K(-3, 2); L(-3, 4); M(-6, 4).
The points of the image J'K'L'M' are:
J'(1, 7); K'(4, 7); L'(4, 9); M'(1, 9).
Comparing the x- and y-coordinates of the pre-image and image points, we can see that the x-coordinate is 7 larger each time and the y-coordinate is 5 larger; this means that the translation <7, 5> has been applied.
Applying this same transformation to STUV, we get point T' at
(6+7, -6+5) = (13, -1)