Question

HELP

What is the standard form equation of the line shown below?

Graph of a line going through negative 2, 3 and 1, negative 3

y + 3 = −2(x − 1)
y = −2x − 1
2x + y = −1
−2x − y = 1

Answer 1

Standard form means:
Ax+By=C
Where A is the coefficient of x, B is the coefficient of y, and C is the y intercept.

It's true that some of those say the same thing but your answer must be in that form because that is what the question asks. So it should be 2x+y=-1

Answer 2

`2x+y=-1`

Explanation:

The given points are

`(-2,3)`

`(1,-3)`

To find the expression of the line shown, first we need to find the slope between the two given points, which the following formula

`m=(y_(2) -y_(1) )/(x_(2) -x_(1) ) =(-3-3)/(1-(-2))=(-6)/(3)=-2`

Now, we have the slope, then we use the point-slope formula, and replace the slope and one point of the given

`y-y_(1)=m(x-x_(1))\\y-3=-2(x-(-2))\\y=-2x-4+3\\y=-2x-1`

But, the standard form is like
`Ax+Bx=C`

So,

`2x+y=-1`

Therefore, the right choice is the third option.