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When g is 4, h is 1/2 and j is 1/3. If g varies jointly with h and j, what is the value of g when h is 2 and j is 3?

User Sunney
by
6.4k points

2 Answers

7 votes
G
\alphaHJ
G=kHJ
where k is a constant of proportionality;
when G=4, H=1/2 and J=1/3
Finding value of k,
4=k*1/2*1/3
4=
(1)/(6)k
k=24
The equation then is;
G=24HJ
When H=2, J=3
G=24*3*2
G=144
User Gage
by
6.4k points
4 votes

Answer:

The value of g is 144 when h is 2 and j is 3 .

Explanation:

As given


When\ g\ is\ 4, h\ is\ (1)/(2)\ and\ j\ is\ (1)/(3) .

If g varies jointly with h and j.


g \propto hj

g = khj

Where k is the constant of proportionality.


When\ g\ is\ 4, h\ is\ (1)/(2)\ and\ j\ is\ (1)/(3) .

Put value in the above


4 = (k)/(2* 3)


4 = (k)/(6)

k = 4 × 6

k = 24

As when h = 2 , j = 3 and k = 24 .

Put in the above

g = 2 × 3 × 24

g = 144

Therefore the value of g is 144 when h is 2 and j is 3 .




User Caleigh
by
7.0k points
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