Question

1/3(n+1)=1/6(3n-5)

I really need help on how to solve this i know the answer but im confused on how we got it

Answer 1

1/3(n+1)=1/6(3n-5)
1/3n+1/3 = 1/2n-5/6
1/3 = 1/6n - 5/6
7/6 = 1/6n
so n = (7/6) / (1/6)
n = 7

Answer 2

Consider the equation
`(1)/(3)(n+1)=(1)/(6)(3n-5).`

1 step. Multiply this equation by 6:

`(6)/(3)(n+1)=(6)/(6)(3n-5),\\ 2(n+1)=3n-5,\\2n+2=3n-5.`

2 step. Separate expressions in such way, that variables are in the left side and the numbers are in the right side:

`2n-3n=-5-2.`

3 step. Add expressions in both sides:

`n\cdot (2-3)=-(5+2),\\-1\cdot n=-7,\\-n=-7.`

4 step. Multiply this equaiton by -1:

n=7.

Answer: n=7.