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What is the completely factored form of x4y – 4x2y – 5y?

y(x2 – 5)(x2 1)


y(x2 5)(x2 – 1)


(x2y – 5)(x2 1)


(x2y 5)(x2 – 1)

User Yarek T
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2 Answers

6 votes

A is correct on edge.


User Mehdi Hadeli
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4 votes
If you would like to write x^4y - 4x^2y - 5y in a completely factored form, you can do this using the following steps:

x^4y - 4x^2y - 5y = y * (x^4 - 4x^2 - 5) = y * (x^2 + 1) * (x^2 - 5)

The correct result would be y * (x^2 + 1) * (x^2 - 5).
User Geoffrey Hing
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