Question

(using the formula given in the lesson, solve the following problem.)

the specific heat of water is 1.00 cal/g °c. if 10 g of water were heated and the water changed by 50°c, how many calories of heat energy would be absorbed by the water?
____ calories
500
50
10

Answer 1

The heat absorbed can be calculate using the equation:


`Q = m\cdot c_e\cdot \Delta T`


`Q = 10\ g\cdot 1(cal)/(g\cdot ^\circ C)\cdot 50\ ^\circ C = \bf 500\ cal`