Question

What is the equation (simplified) the inverse of y=2x^2?

Answer 1

`2x^2=y\ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=(y)/(2)\\\\\boxed{x=\sqrt{(y)/(2)}}\\\\x=(√(y))/(\sqrt2)=(√(y)\cdot\sqrt2)/(\sqrt2\cdot\sqrt2)\to\boxed{x=(√(2y))/(2)}\\\\\\\boxed{f(x)=2x^2\to f^(-1)(x)=(√(2y))/(2)}`