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What is the sum of the first 5 terms of a geometric series with a a1 = 10 and r = 1/5 ?
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What is the sum of the first 5 terms of a geometric series with a a1 = 10 and r = 1/5 ?

User BraveSirFoobar
by
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1 Answer

4 votes
Sn=
(a1(1-r^n))/(1-r )

a1=10
r=1/5
n=5

Sn=
(10(1-(1/5)^5))/(1-(1/5) )
Sn=12.496
User Gabsferreira
by
8.5k points
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