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A box, initially at rest, has 23.4 N of force exerted on it for 2.56 s. If the box has a mass of 7.33 kg, what was its velocity at this time?

User Andie Vanille
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1 Answer

11 votes
11 votes

Given:

The force applied on the box, F=23.4 N

The time duration for which the force is applied, t=2.56 s

The initial velocity of the box, u=0 m/s

The mass of the box, m=7.33 kg

To find:

The velocity of the box.

Step-by-step explanation:

From Newton's second law, the force applied to the box is given by,


F=ma

Where a is the acceleration of the box due to the applied force.

On substituting the known values,


\begin{gathered} 23.4=7.33* a \\ \Rightarrow a=(23.4)/(7.33) \\ =3.19\text{ m/s}^2 \end{gathered}

From the equation of motion, the final velocity of the box is given by,


v=u+at

On substituting the known values,


\begin{gathered} v=0+3.19*2.56 \\ =8.17\text{ m/s} \end{gathered}

Final answer:

The velocity of the box is 8.17 m/s

User Sasha Kos
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