Question

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. What is the acceleration of the crate?

Answer 1

a = 6 m/s/s

Step-by-step explanation:

As we know that the steel crate is pushed along the cement floor

The applied force on the crate is towards right and its magnitude is 1860 N

while the force of friction on the crate due to floor is towards left and its magnitude is 480 N

now the net force on the crate is given as

`F_(net) = 1860 - 480 = 1380 N`

now from Newton's II law we know that

`F_(net) = ma`

now plug in all values in it

`1380 = 230 a`

`a = (1380)/(230)`

`a = 6 m/s^2`

Answer 2

To answer this specific problem, the acceleration of the crate is 140.6727828746177. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.