Question

Please solve: c + (4 – 3c) – 2 = 0

Answer 1

ok so first distribute invisible 1
c+1(4-3c)-2=0
c+4-3c-2=0
group like terms
c-3c+4-2=0
add like terms
-2c+2=0
minus 2 from both sides
-2c=-2
divide both sides by -2
c=1