Question

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B^2 to both sides of the equation in step 4, what is the constant on the right side of the equation? a. -32b. 112c. 160

Answer 1

1. Write the equation in the form:

`Ax^2+Bx+C=0`

`2x^2+8x-12=0`

You indentify A is 2 and B is 8 in the given equation:

`A=2`
`B=8`

2. 4A is 8 (4*2=8):

`8\lbrack2x^2+8x-12\rbrack=8\lbrack0\rbrack`

`16x^2+64x-96=0`

3.

`16x^2+64x=96`

4. B^2 is 64 (8*8=64)

`\lbrack16x^2+64x\rbrack+64=\lbrack96\rbrack+64`
`16x^2+64x+64=160`After step 4, the constant on the right side of the equation is 160